Frequency test Lotto Plus
Does the distribution of hits for all numbers match the model?
What would you like to check?
Enter or load your numbers in the analyzer. The latest draw report describes the actual draw, not your selection.
Explore all statistics — guided topics
These pages describe the history of this game. They do not predict future numbers. Use the selection tool on a page to compare your own numbers.
Numbers and gaps
Start with frequency and gaps: how often each number appeared in the selected historical sample.
Draw structure
Compare sum, parity, endings and range. On a page with a selection comparison, open it to check your numbers.
Relationships and random model
Explore pairs, triples and partners, then the random model. Historical relationships do not improve future odds.
Draws and tools
Read the latest draw report for the actual drawn numbers. Use the analyzer and matching draws for your own selection.
- Game
- Lotto Plus
- Number pool
- 49
- Selected range
- 50 most recent
- Draws in the sample
- 50
- From
- 2026-06-09T20:00:00Z
- To
- 2026-10-01T20:00:00Z
- Latest draw in the sample
- 2026-10-01T20:00:00Z
- Calculated at
- 2026-10-01T23:56:26+02:00
- Source
- Service draw archive
- Freshness
- Checking…
Number frequency test
Each of the 49 numbers should occur equally often under the random model: expected hits E = N·k/m for k = 6. T sums squared standardized deviations for all numbers with the (m−1)/m correction, because numbers in one draw are not independent.
Statistic T (N = 50 draws)
46,541
degrees of freedom df = 48 · (T − df)/√(2·df) = -0,15
Asymptotic p-value
0,532725
A value of 0.000000 means p is below 0.0000005 after rounding to six decimal places — not proof that such a T is impossible.
Range too short for a reliable test: p-value and calibration disabled.
Calibration by model simulation
—
threshold c95 = — · c99 = — · max z = 2,210
Numbers with the largest contribution to T
z = (hits − E)/SD, where SD = √(N·p·(1−p)), p = k/m. Contribution = z²·(m−1)/m, calculated from raw hits. Percent is the share of the sum of all numbers' contributions.
| number | hits | E | z | contribution | % T |
|---|
The contribution table loads from a separate data file when the page opens. It is not available without JavaScript; the measures above come from the analysis file.
Methodology
For each number n ∈ {1…m}: p = k/m, E = N·p, SD = √(N·p·(1−p)), z = (hits − E)/SD. Statistic T = ((m−1)/m)·Σz², degrees of freedom df = m−1. The (m−1)/m correction results from drawing k numbers out of m without replacement.
The p-value is asymptotic: calculated from a chi-squared distribution with df degrees of freedom, which approximates the distribution of T for large N. The calibrated percentile and the c95/c99 thresholds come from a simulation of the random model. The p-value is not the probability that the random model is true — it tells how often the model gives a T at least this large.
For a range of years, T, df, z, and contributions are calculated from summed annual counters; the p-value, percentile, and thresholds are not available for such a combination. In short ranges, we show the facts and T, but disable the p-value and calibration.
Interactive tools
Explore the same data actively. The tools describe history and the random model; they do not predict the next result.
My selection — check its properties against history
This describes the entered selection and its position in the historical sample. It does not increase its chance.
History player — move through past draws
Choose a year, use the slider or start automatic playback. This is a presentation of recorded results, not a forecast.
Open the module to load the available years.
Random-model simulator — see ordinary random variation
Generate independent draws with the rules of this game and compare observed counts with the common expected value. Every run is different.
What do these numbers show?
- Frequency-test statistic for 50 draws: T = 46.541 at df = 48. Method: chi-square with the (m−1)/m correction for drawing 6 of 49 numbers without replacement.
- Descriptive standardization (T − df)/√(2·df) = -0.15. A positive value means T is above the expected df; a negative value means it is below. This is descriptive, not a test result.
- Asymptotic p-value: 0.532725 (from a chi-square distribution with df degrees of freedom). This is not the probability that the random model is true.
- Largest standardized deviation in the range: max z = 2.210.
These are historical data. Each draw is independent of previous draws, so these numbers do not tell us what will be drawn next.
How do I use this page?
- Choose the number of recent draws or a year range.
- Compare T with the df degrees of freedom: under the random model T is usually close to df.
- Check the asymptotic p-value and calibrated percentile; they show how unusual T is under the random model.
- Use the contribution table to see which numbers differ most from expected hits.
What this page does not do: does not point to numbers to play and does not increase the chance of winning.
How to read statistical measures
Random model
Expected value
Deviation
Percentile
Typicality