Is an overdue number more likely next?

No, when draws are independent and rules have not changed.

Why can a record gap be long?

Many numbers over many draws create many opportunities for a rare event to occur.

How long should the gap between number appearances be?

Under independent draws, waiting time to another appearance follows a geometric distribution. A long current gap does not increase the probability in the next draw.

Hit probability

For one Lotto number, the appearance probability in a draw is

p = \frac{6}{49} \approx 0.12245

Geometric distribution

If G is the number of draws up to and including the next appearance,

P (G = g) = {(1 - p)}^{g - 1} p

. Mean waiting time is 1/p, about 8.17 draws.

Example

The probability that a number is absent from 10 consecutive draws is

{(1 - \frac{6}{49})}^{10} \approx 0.271

. Such a gap is compatible with randomness.

Memorylessness

After ten draws without that number, its probability in the eleventh draw remains 6/49. The geometric distribution is memoryless.

Comparing with data

The analysis compares empirical gap lengths with expected frequencies. Assess the full distribution rather than a single record.

Limitations

The model assumes constant p and independent draws. An incomplete history or a pool-size change requires separating periods.

Frequently asked questions

Is an overdue number more likely next?: No, when draws are independent and rules have not changed.
Why can a record gap be long?: Many numbers over many draws create many opportunities for a rare event to occur.

Check it on real draw data

Choose a draw range in Lotto Lab PRO and compare the observed result with the random model.

Open Lotto Lab PRO

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Last updated: 20.10.2026